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(a+b)(a^2-ab+b^2)=
Sumamos y restamos al segundo paréntesis 2ab:
(a+b)(a^2+2ab+b^2-ab-2ab)=
Factorizamos el TCP:
(a+b)[(a+b)^2-3ab]
Sustituimos:
(√10)[(√10)^2-3(2)]=
√10(10-6)=
√10(4)=4√10
2. Factorizamos:
(a+b)(a^2-ab+b^2)=0
Sumamos y restamos 2ab:
(a+b)(a^2+2ab+b^2-2ab-ab)=0
Factorizamos el TCP:
(a+b)[(a+b)^2-3ab]=0
Sustituimos a+b=√6
√6[6-3ab]=0
Pasamos dividiendo √6
6-3ab=0
3ab=6
ab=2