Respuesta:
a) 2/3*2/3*2/3 = [tex](2/3)^2[/tex] = [tex](2^2)/(3^2)[/tex] = 4/9
b) (-0,01)(-0.01) = [tex](-0,01)^2[/tex] = 0,0001
c) (-1/3)(-1/3)(-1/3)(-1/3)(-1/3) = [tex](-1/3)^{5}[/tex] = [tex](-1^5)/(-3^5)[/tex] = -1/-243 = 0.00411522633
Espero haberte ayudado, si es así corona please
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Verified answer
Respuesta:
a) 2/3*2/3*2/3 = [tex](2/3)^2[/tex] = [tex](2^2)/(3^2)[/tex] = 4/9
b) (-0,01)(-0.01) = [tex](-0,01)^2[/tex] = 0,0001
c) (-1/3)(-1/3)(-1/3)(-1/3)(-1/3) = [tex](-1/3)^{5}[/tex] = [tex](-1^5)/(-3^5)[/tex] = -1/-243 = 0.00411522633
Espero haberte ayudado, si es así corona please