[tex]\frac{\left(-4\right)^3\left(\left(-4\right)^2\right)^3}{\left(-4\right)^9}[/tex]
[tex]=\frac{\left(\left(-4\right)^2\right)^3}{\left(-4\right)^6}[/tex]
[tex]\boxed{ =1}[/tex]
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SIMPLIFICAR
[tex]\frac{\left(-4\right)^3\left(\left(-4\right)^2\right)^3}{\left(-4\right)^9}[/tex]
[tex]=\frac{\left(\left(-4\right)^2\right)^3}{\left(-4\right)^6}[/tex]
[tex]\boxed{ =1}[/tex]