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an=79
an=a1+(n-1)d
79=7+(n-1)6
79-7=6n-6
72=6n-6
72+6=6n
78=6n
n=78/6
n=13
la posicion 13 se habla de a13=79
a1+a8=21
a1+a1+7d=21 => 2a1+7d=21
pero a3=6 a1+2d=6
a1=6-2d
2(6-2d)+7d=21
12-4d+7d=21
3d=21-12
3d=9
d=3
a1=6-2*3=6-6=0
entonce a1=0,a2=3,a3=6,a4=9,a5=12,a6=15,a7=18,a8=21