Respuesta:
saldria
[tex] \sqrt{2} [/tex]
Explicación paso a paso:
Log√2( x⁵ ) Logx⁵ ( 2x² ) = 2Log4( 256 )
[tex] \frac{ log_{10}(x {}^{5} ) }{ log( \sqrt{2} ) } \times \frac{ log(2x {}^{2} ) }{ log(x {}^{5} ) } = 2 log_{4}(4 {}^{4} ) [/tex]
1 / Log√2 × Log( 2x² ) = 2 × 4
2x² = √2⁸
2x² = 16
x² = 8
x = +2√2
x = 2 √2
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Verified answer
Respuesta:
saldria
[tex] \sqrt{2} [/tex]
Explicación paso a paso:
Log√2( x⁵ ) Logx⁵ ( 2x² ) = 2Log4( 256 )
[tex] \frac{ log_{10}(x {}^{5} ) }{ log( \sqrt{2} ) } \times \frac{ log(2x {}^{2} ) }{ log(x {}^{5} ) } = 2 log_{4}(4 {}^{4} ) [/tex]
1 / Log√2 × Log( 2x² ) = 2 × 4
2x² = √2⁸
2x² = 16
x² = 8
x = +2√2
x = 2 √2