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a1 = d
an = a1 + (n - 1)a1
Tercer termino n = 3; a3 = 36
36 = a1 + (3 - 1)a1
36 = a1 + (2)a1
36 = a1 + 2a1
36 = 3a1
a1 = 36/3
a1 = 12