Ayuda por favor como resuelvo esta ecuación X^2-3X+1=0
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x = (-b ± √b^2 -4ac)/2a
Donde:
a= 1
b=-3
c=1
x= 3 ± √9 - 4x1x1 /2
x = 3 ±5 / 2
Entonces las soluciones serían:
x1: (3+√5)/2
x2: (3-√5)/2