Question

ayuda plis es para hoy

Answer 1

Respuesta:

[tex]R=(\sqrt{11} +\sqrt{5} ) (\sqrt{11}-\sqrt{5} )+(\sqrt{5} +2)(\sqrt{5}-2) \\R=(\sqrt{11})^{2} -(\sqrt{5})^{2} +(\sqrt{5})^{2} -2^{2} \\R=\sqrt{121}-\sqrt{25} +\sqrt{25} -4\\R=11-5+5-4\\R=6+1\\R=7[/tex]

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[tex]F=(a+1)(a-1)-(a+3)(a-3)\\F=a^2-1-\left(a+3\right)\left(a-3\right)\\F=a^2-1-a^2+9\\F=-1+9\\F=8[/tex]

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[tex]Q=(x+5)(x-5)-(x+9)(x-9)\\Q=x^2-25-\left(x+9\right)\left(x-9\right)\\Q=x^2-25-x^2+81\\Q=-25+81\\Q=56[/tex]

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[tex]A=(x+4)(x+3)-(x+5)(x+2)\\A=x^2+7x+12-\left(x+5\right)\left(x+2\right)\\A=x^2+7x+12-x^2-7x-10\\A=12-10\\A=2[/tex]

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[tex]A=(x-1)^{2} -(x+2)^{2} \\A=x^2-2x+1-\left(x+2\right)^2\\A=x^2-2x+1-\left(x^2+4x+4\right)\\A=x^2-2x+1-x^2-4x-4\\A=-2x+1-4x-4\\A=-6x-3[/tex]

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[tex](x-5)(x+5)-(x+6)(x-6)\\=x^2-25-\left(x+6\right)\left(x-6)\right\\=x^2-25-x^2+36\\=-25+36\\=11[/tex]

Explicación paso a paso:

Espero haberte ayudado <3