Question

ayuda HALLAR EL AREA SOMBREADA DE LAS SIGUIENTES FIGURAS​

Answer 1

Verified answer

Respuesta:

Explicación paso a paso:

[tex]Para -el -rectangulo:[/tex]

[tex]Base: b =10cm[/tex]

[tex]Altura: h = \frac{6cm}{2} = 3cm[/tex]

[tex]Area-sombreada: As=?[/tex]

[tex]As = \frac{b*h}{2} = \frac{10cm*3cm}{2}[/tex]

[tex]As = \frac{30cm^{2} }{2}[/tex]

[tex]As = 15cm^{2}[/tex]

-------------------------------------------------------------------------------------------------------

[tex]Para-el-cuadrado:[/tex]

[tex]Area: A = 16 cm^{2}[/tex]

[tex]Lado: L = ?[/tex]

[tex]L = \sqrt{A}[/tex]

[tex]L = \sqrt{16cm^{2} } = 4cm[/tex]

[tex]Area-sombreada: As=?[/tex]

[tex]As =Area-del -triangulo ABD -menos- Area-del-triangulo ABM[/tex]

[tex]As = \frac{AB * AD}{2} -\frac{AD*AM}{2} = \frac{4cm* 4cm}{2} -\frac{4cm*2cm}{2}[/tex]

[tex]As = \frac{16cm^{2} }{2} -\frac{8cm^{2} }{2} = 8cm^{2} -4cm^{2}[/tex]

[tex]As = 4cm^{2}[/tex]

----------------------------------------------------------------------------------------------------------

[tex]Para-el-paralelogramo:[/tex]

[tex]Area: A = 64cm^{2}[/tex]

[tex]Area-sombreada: As=?[/tex]

[tex]As = 2 ( \frac{A}{4} ) = 2 ( \frac{64cm^{2} }{4} ) = \frac{128cm^{2} }{4}[/tex]

[tex]As = 32cm^{2}[/tex]