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x² - x - 1
Completando:
x⁴ + 0x³ - x² - 2x - 1
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x² - x - 1
1 I 1 0 - 1 - 2 -1
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I
1 I 1 1
I ----
1 I 1 1 1
I -----
I 1 1 1
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I 1 1 1 0 0 ⇒ Exacta
q(x) = 1x² + 1x + 1
q(x) = x² + x + 1
T.I. (Termino Independiente) = 1
Residuo = 0