Respuesta:
ojala y te sirva
Explicación paso a paso:
[tex] \sqrt[2]{8 {n}^{3} } = \sqrt{4(2) {n}^{2}n } = 2n \sqrt{2n} [/tex]
[tex] \sqrt[3]{25x5} = \sqrt[3]{ {5}^{3} x} = 5 \sqrt[3]{x} [/tex]
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Respuesta:
ojala y te sirva
Explicación paso a paso:
[tex] \sqrt[2]{8 {n}^{3} } = \sqrt{4(2) {n}^{2}n } = 2n \sqrt{2n} [/tex]
[tex] \sqrt[3]{25x5} = \sqrt[3]{ {5}^{3} x} = 5 \sqrt[3]{x} [/tex]