Question

Ayo , menentukan hasil (2x - 3)³ dengan cara perkalian biasa!
(2x - 3)³ = (...) (2x - 3) (2x - 3)
= [(2x - 3) (....)] (2x - 3)
= [2x(2x - 3) - 3(2x - 3)] (...)
= [4x² - .... - 6x + ...] (2x - 3)
= (4x² - ... + 9) (2x - 3)
= ... (2x - 3) - 12x(2x - 3) + 9(....)
= 8x³ - 12x² - ... + 36x + ... - 27
= 8x³ - (12 + ... )x² + ( ... + 18)x - 27
= 8x³ - ... + 54x - ...

tolong dong isiin , yang titik titik ny ya :) , TERIMA KASIH SEBELUMNYA

Answer 1

(2x - 3)³ = (2x-3) (2x - 3) (2x - 3)
= [(2x - 3) (2x-3)] (2x - 3)
= [2x(2x - 3) - 3(2x - 3)] (2x-3)
= [4x² - 6x - 6x + 9 ] (2x - 3)
= (4x² - 12x + 9) (2x - 3)
= 4x (2x - 3) - 12x(2x - 3) + 9(2x-3)
= 8x³ - 12x² - 24x^2 + 36x + 18x - 27
= 8x³ - (12 + 24 )x² + ( 36 + 18)x - 27
= 8x³ - 36 + 54x - 27
= 8x^3 + 54x - 63