Question

Ayo gan cepat jwb nya ..

Answer 1

1. X^2-4x+1
X1,2 = -b +/- √b^2-4ac /2a
= 4+/- √16-4 / 2 (dikuadratkan semua)
X1. = 16+12 / 4 = 7
X2. = 16-12 / 4. = 1
2) x+y >_ -1
x^2-4x+1 >_ 4 _
'''''''''''''''''''''''''''''''''''''''''''''''
-x^2+5x+2y >_ 0
x^2-5x-2y >_ 0

3) x^2-5x >_ 2y
x^2-5x/2 >_y

4) x = 7
7>_ y

x= 1
-2>_ y

Answer 2

X+y ≥ -1
y ≥ -x-1
-x-1 ≤ y
y ≤ x²-4x+1

-x-1 ≤ y dan y ≤ x²-4x+1, maka -x-1 ≤ x²-4x+1
-x-1 ≤ x²-4x+1
x²-4x+1 ≥ -x-1
x²-4x+1+x+1 ≥ 0
x²-3x+2 ≥ 0
(x-1)(x-2) ≥ 0
puncak:
x = -b/2a
x = 3/2
y = b²-4ac/-4a
y = 9-8/-4
y = -1/4
daerahnya yg berada di atas kurva