Asam Hx 0,1 M mempunyai pH yang sama dengan larutan HCl 0,001 M. tentukanlah nilai tetapan ionisasi (Ka) asam Hx itu!
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![HCl =10^{-3}~M \\ \\ ~[H^+]=10^{-3}~M \\ \\ \textsf{karena pH sama maka}~[H^+]_{HCl}=[H^+]_{HA}=10^{-3}~M \\ \\ ~[H^+]= \sqrt{Ka.M} \\ \\ 10^{-3}= \sqrt{Ka.10^{-1}} \\ \\ 10^{-6}=Ka.10^{-1} \\ \\ Ka=10^{-5}](https://tex.z-dn.net/?f=HCl+%3D10%5E%7B-3%7D%7EM+%5C%5C++%5C%5C+%7E%5BH%5E%2B%5D%3D10%5E%7B-3%7D%7EM+%5C%5C++%5C%5C+%5Ctextsf%7Bkarena+pH+sama+maka%7D%7E%5BH%5E%2B%5D_%7BHCl%7D%3D%5BH%5E%2B%5D_%7BHA%7D%3D10%5E%7B-3%7D%7EM+%5C%5C++%5C%5C+%7E%5BH%5E%2B%5D%3D+%5Csqrt%7BKa.M%7D+%5C%5C++%5C%5C+10%5E%7B-3%7D%3D+%5Csqrt%7BKa.10%5E%7B-1%7D%7D+%5C%5C++%5C%5C+10%5E%7B-6%7D%3DKa.10%5E%7B-1%7D+%5C%5C++%5C%5C+Ka%3D10%5E%7B-5%7D++ "HCl =10^{-3}~M \\ \\ ~[H^+]=10^{-3}~M \\ \\ \textsf{karena pH sama maka}~[H^+]_{HCl}=[H^+]_{HA}=10^{-3}~M \\ \\ ~[H^+]= \sqrt{Ka.M} \\ \\ 10^{-3}= \sqrt{Ka.10^{-1}} \\ \\ 10^{-6}=Ka.10^{-1} \\ \\ Ka=10^{-5}")
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