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paling sedikit = U1 = a = 70 gram
paling banyak = U3 = ar²
U2 = ar
U1+U2+U3 = 910
a+ar+ar² = 910
a(1+r+r²) = 910
1+r+r² = 910/a
1+r+r² = 910/70
1+r+r² = 13
r²+r-12=0
(r+4)(r-3)=0
r=-4 (dalam kasus ini tidak logis jika r=-4) atau r=3
maka paling banyak = U3 = ar² = 70.(3)²=70.9 =630 gram