Question

Apabila suatu kerucut memiliki tinggi 10cm dan Jari2 6 cm maka hitunglah luas prmukaan dan volumenya MOHON DI BANTU

Answer 1

Tinggi = 10 cm
Jari2 = 6 cm
s = 11,6 cm
=\/6² + 10²
=\/36 + 100
=\/136 cm
= 11,6 cm

L Permukaan
= (3,14 x 36) + ((3,14 x 6) x 11,6)
= 113,04 + 218,544
= 331,584 cm²

V
= 1/3 x (3,14 x 36) x 10
= 1/3 x 113,04 x 10
= 1/3 x 1130,4
= 376,8 cm³

Answer 2

Dik:
t = 10 cm
r = 6 cm

DIt:
Luas permukaan (Lp) = ?
Volume (V) = ?

Jwab:
Kita cari dulu "s" nya:
s = √(r²+t²)
s = √(6²+10²)
s = √(36+100)
s = √136
s = 11,6 cm

Lp = πr² + πrs
Lp = 3,14 x 6² + 3,14 x 6 x 11,6
Lp = 113,04 + 218,544
Lp = 331,584 cm²

V = 1/3 x πr²t
V = 1/3 x 3,14 x 6² x 10
V = 1/3 x 3,14 x 36 x 10
V = 376,8 cm³


Salam....... ^^