Respuesta:
A)
[tex]\frac{ {2a}^{2} }{3(2a + b)(a + 2b)} [/tex]
B)
[tex] \frac{3(a + 7)}{(a + 5) ^{2} } [/tex]
C)
[tex]\frac{ {x}^{3} }{a( {x}^{2} + {a}^{2}) } [/tex]
D)
[tex]\frac{( - a + x)b ^{3} }{ {a}^{2}( {a}^{2} - 2ax + {x}^{2} ) } [/tex]
E)
[tex]\frac{ {x}^{2} + 2xy + {y}^{2} }{ {y}x } [/tex]
F)
[tex] \frac{3(a + b)}{2( 3a + 2b)} [/tex]
G)
[tex] \frac{5(p + 3)}{(p + 5) (p - 2q)} [/tex]
H.
[tex] \frac{(2m + 3n)(m - 1)}{3 {m}^{2} } [/tex]
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Respuesta:
✦✧✧HOᒪᗩ Juan! Listo para aprender? Vamos!✧✧✦ ☑️
A)
[tex]\frac{ {2a}^{2} }{3(2a + b)(a + 2b)} [/tex]
B)
[tex] \frac{3(a + 7)}{(a + 5) ^{2} } [/tex]
C)
[tex]\frac{ {x}^{3} }{a( {x}^{2} + {a}^{2}) } [/tex]
D)
[tex]\frac{( - a + x)b ^{3} }{ {a}^{2}( {a}^{2} - 2ax + {x}^{2} ) } [/tex]
E)
[tex]\frac{ {x}^{2} + 2xy + {y}^{2} }{ {y}x } [/tex]
F)
[tex] \frac{3(a + b)}{2( 3a + 2b)} [/tex]
G)
[tex] \frac{5(p + 3)}{(p + 5) (p - 2q)} [/tex]
H.
[tex] \frac{(2m + 3n)(m - 1)}{3 {m}^{2} } [/tex]
Espero Haberte Ayudado!
ATTE: Misheru, Tu Asistente Escolar.