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perimetro= suma de lados
p=16*R
368=16*R
R=368/16=23 m
calculamos el area del cuadrado
A1=L^2=(2R)^2=(2*23)^2=2116 m2
calculamos area del triangulo
a2=(b*h)/2=4R*3R/2=(12R^2)/2=6R^2=6*23^2=3174 m2
sumamos las 2 areas
2116+3174=5290 m2 ( resultado)