" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2x^2-3x-4=0
segun la formula general
x=(-b+-raiz(b^2-4ac))/2a
donde
a=2
b=-3
c=-4
remplazamos
x=3+-raiz((3)^2-4(2)(-4))/2a
x=(3+-raiz(9+16))/2(2)
x=(3+-raiz(25))/4
x1=(3+5)/4
x1=8/4
x1=2
x2=(3-5)/4
x2=-2/4
x2=-1/2
saludos