Question

Alguien me podría ayudar? Porfa

Answer 1

Verified answer

Respuesta:

ejercicio 1 y 2

[tex]{81}^{-2} \times {3}^{-7} =

({3}^{4})^{ - 2} \times {3}^{ - 7} =

{3}^{ - 8} \times {3}^{ - 7} = {3}^{ - 15}[/tex]

[tex]16 \times{8}^{ - 2}\times{2}^{2} =

{2}^{4} \times { ({2}^{3} })^{ - 2} \times {2}^{2} =[/tex]

[tex]{2}^{4} \times{2}^{ - 6} \times {2}^{2} = [/tex]

suma de exponentes 4+(-6)+2=4-6+2=6-6=0

[tex]= {2}^{0} = 1[/tex]

Explicación paso a paso:

ejercicio 3

[tex]{25}^{- 3} \times {5}^{ - 6} \times 125 = [/tex]

[tex] ({5}^{2})^{-3} \times {5}^{ - 6} \times {5}^{3} = [/tex]

[tex] {5}^{- 6} \times {5}^{ - 6} \times {5}^{3 = } [/tex]

[tex] = {5}^{ - 9} [/tex]