@=alfa
c) [email protected], jeśli @ należy do (180,270) i [email protected]@=2
d) [email protected], jeśli @ należy do (270,360) i [email protected]@=3
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III ćwiartka, więc sinus jest ujemny
III ćwiartka, wiec cosinus również jest ujemny
d)![\alpha\in(\frac{3}{2}\pi;\pi)\\4cos^2\alpha-sin^2\alpha=3\\4cos^2\alpha-(1-cos^2\alpha)=3\\4cos^2\alpha-1+cos^2\alpha=3\\5cos^2\alpha=4\\cos^2\alpha=\frac{4}{5}\\cos=\frac{2\sqrt5}{5}\ lub\ cos=-\frac{2\sqrt{5}}{5} \alpha\in(\frac{3}{2}\pi;\pi)\\4cos^2\alpha-sin^2\alpha=3\\4cos^2\alpha-(1-cos^2\alpha)=3\\4cos^2\alpha-1+cos^2\alpha=3\\5cos^2\alpha=4\\cos^2\alpha=\frac{4}{5}\\cos=\frac{2\sqrt5}{5}\ lub\ cos=-\frac{2\sqrt{5}}{5}](https://tex.z-dn.net/?f=%5Calpha%5Cin%28%5Cfrac%7B3%7D%7B2%7D%5Cpi%3B%5Cpi%29%5C%5C4cos%5E2%5Calpha-sin%5E2%5Calpha%3D3%5C%5C4cos%5E2%5Calpha-%281-cos%5E2%5Calpha%29%3D3%5C%5C4cos%5E2%5Calpha-1%2Bcos%5E2%5Calpha%3D3%5C%5C5cos%5E2%5Calpha%3D4%5C%5Ccos%5E2%5Calpha%3D%5Cfrac%7B4%7D%7B5%7D%5C%5Ccos%3D%5Cfrac%7B2%5Csqrt5%7D%7B5%7D%5C+lub%5C+cos%3D-%5Cfrac%7B2%5Csqrt%7B5%7D%7D%7B5%7D)
IV ćwiartka, więc cosinus jest dodatni
IV ćwiartka, więc sinus jest ujemny
c) 9 sin²α - 5 cos²α = 2 , tgα = ? α ∈ (180°, 270°)
9 sin²α - 5(1 - sin²α) = 2
9 sin²α - 5 + 5 sin²α = 2
14 sin²α = 7 /:14
sin²α = ½ /√
sinα = - 1/√2 = - √2 / 2
cos²α = 1 - sin²α
cos²α = 1 - ½
cos²α = ½ ⇒ cosα = - √2 /2
sinα - √2 /2
tgα = ----------- = -------------- = 1
cosα - √2 /2
d) 4 cos²α - sin²α = 3 , ctgα = ? α ∈ ( 270°, 360°)
4(1 - sin²α) - sin²α = 3
4 - 4 sin²α - sin²α = 3
- 5 sin²α = -1 /:(-5)
sin²α = ⅕ /√
sinα = - 1/ √5 = - √5 / 5
cos²α = 1 - sin²α
cos²α = 1 - ⅕
cos²α = ⅘ /√
cosα = 2/ √5 = 2√5 / 5
cosα 2√5 / 5 2√5 -5
ctgα = ----------- = ------------- = -------- · --------- = -2
sinα - √5 / 5 5 √5