Alas suatu prisma berbentuk belah ketupat yang kelilingnya 52cm dan panjang salah satu diagonalnya 24 cm. jika tinggi prisma 15 cm, maka volum prisma adalah
khoirunnisa580
K = 4×s 52 = 4×s s = 52 : 4 = 13 cm (1/2d₂)² = s² - (1/2d₁)² = 13² - 12² = 169 - 144 1/2d₂ = √25 = 5cm d₂ = 5x2 = 10 cm La = 1/2×d₁×d₂ = 1/2× 24 × 10 = 12 × 10 = 120 cm² V = La × t = 120 × 15 = 1800 cm³
52 = 4×s
s = 52 : 4 = 13 cm
(1/2d₂)² = s² - (1/2d₁)²
= 13² - 12²
= 169 - 144
1/2d₂ = √25 = 5cm
d₂ = 5x2 = 10 cm
La = 1/2×d₁×d₂
= 1/2× 24 × 10
= 12 × 10
= 120 cm²
V = La × t
= 120 × 15
= 1800 cm³