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Mm I₂ = 253.80 g/mol
AlI₃ = 407.80 g/mol
g AlI₃ = 2,5 g I₂ x 1mol I₂ x 2 mol AlI₃ x 407.70 g AlI₃
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253.80 g I₂ 3 mol I₂ 1 mol AlI3
g = 2.67 de AlI₃