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log 2= p
log 3= q
³log 12=...?
= log 12/log 3
= log (4×3)/log 3
= log 2²+log 3/log 3
= 2.log 2+log 3/log 3
= 2p+q / q (A)
15) ³log 1/27=...?
= ³log 27⁻¹
= ³log (3³)⁻¹
= ³log 3⁻³
= -3.³ log 3
= -3.1= -3 atau 1/3
16) 4⁻²= 1/16
bᵃ= c
ᵇlog c= a
= ⁴log 1/16= -2 (A)