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(-b+√b²-4×a×c)/2a
a=3
b=-1
c=-1
[-(-1)+√(-1²)-4×3×(-1)]/2(3)
[1+√1+12]/6
[1+√13]/6
X₁= (1+√13)/6
X₂= (1-√13)/6
SEMOGA MEMBANTU.
a = 3
b = -1
c = -1