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Didapat:
Dengan Rumus ABC, diperoleh:
αβ = (a + 2)/(a - 1)
ditanya : nilai a ?
dijawab
αβ(β + α) = -20
((a + 2)/(a - 1))(-4/(a - 1)) = -20
-4(a + 2)/(a - 1)² = -20
(-4a - 8)/(a² - 2a + 1) = -20
-4a - 8 = -20a² + 40a - 20
-20a² + 44a - 12 = 0
bagi -4 kedua ruas
5a² - 11a + 3 = 0
pakai rumus ABC