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Akar:
Tinjau koefisien x:
-4β = 7-3a
4β = 3a - 7
β = ¼(3a-7)
Dan, tinjau konstanta:
3β² = 2a+2
Substitusikan:
Ambil yang a > 1
Maka,
a = 5
Sehingga,
2a - 3
= 2(5) - 3
= 10 - 3
= 7 [D]
α+β= -b/a
3β+β= -(7-3a)/1
4β=-7+3a
β= (-7+3a)/4
α.β=c/a
3β.β=(2a+2)/1
3β^2=2a+2
3((-7+3a)/4)=2a+2
(-21+9a)=4 × (2a+2)
-21+9a=8a+8
9a-8a=21+8
a=29
jadi, 2a-3=2(29)-3=58-3=55