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p + 2q = 6 ... (1)
p + q = -b/a
= - [ -( m + 5 ) ] / 2
= 1/2 ( m + 5 ) ---> 2p + 2q = m + 5 ... (2)
Pers (2) dan (1) :
2p + 2q = m + 5
p + 2q = 6
---------------------- (-)
p = m - 1 ... (3)
Pers (1) :
p + 2q = 6 ---> p = m - 1
( m - 1 ) + 2q = 6
2q = 7 - m ---> q = 1/2 ( 7 - m ) ... (4)
pq = c/a = 5/2 ---> masukkan pers (3) dan (4)
( m - 1 ) [ 1/2 ( 7 - m ) ] = 1/2 . 5 ---> 1/2 dicoret
( m - 1 ) ( 7 - m ) = 5 ---> dikali (-1)
( m - 1 ) ( m - 7 ) = -5
m² - 8m + 7 = -5
m^2 - 8m + 12 = 0
( m - 2 ) ( m - 6 ) = 0
m1 = 2 atau m2 = 6
Nilai 2m ---> 4 atau 12