Question

A.Hitung PH larutan Ba(OH) = 0,05 m.
b. Hitung PH 100 ml Lar.AS asetat Ka = 1,75x 10–5=0,2m.​

Answer 1

A. Ba(OH)2 basa kuat

Valensi = jml OH- atau H+ = 2

[OH-] = valensi × M

= 2 × 0,05 = 0,1 = 10^-1

pOH = - log [OH-] = 1

pH = 14 - pOH = 4- 1 = 13

B. Asam lemah

[H+] = akar (Ka × M)

= akar (1,75 × 10^-5 × 0,2)

= akar (0,35 × 10^-5)

= akar (3,5 × 10^-6)

= 1,87 × 10^-3

pH = - log [H+] = 3 - log 1,87

Answer 2

a. basa kuat

b. asam kuat