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Jawab :
y' = 9 ( x2 + 3x + 5 )8 ( 2x + 3)
misalkan : u = 2x + 3
du = 2 dx (di turunkan)
maka : dx = 1/2 du
= Г(2x + 3)³²¹ dx
= Г(u)³²¹ . 1/2 du
= 1/2 Γ(u)³²¹ . du
= 1/2 [1/322 . u³²² ] + c
= 1/644 . u³²² + c
masukkana aja lagi
= 1/644 . (2x + 3) + c
ket= tanda Г itu integral
ya gini aja contohnya