AndinaTasya
Q-AB = m . Δt . C es = 0.5 . (0-(-10)) . 2100 = 10 . 1050 = 10500 J = 10,5 kJ Q-BC = m . L = 0,5 . 336000 = 168000 J = 168 kJ Q-ABC = Q-AB + Q-BC = 10,5 kJ + 168 kJ = 178,5 kJ (D) *Keterangan m = massa Δt = suhu akhir - suhu awal C es = massa jenis es L = kalor lebur
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Septiannn
wow good answer, thank you for your help
= 0.5 . (0-(-10)) . 2100
= 10 . 1050
= 10500 J
= 10,5 kJ
Q-BC = m . L
= 0,5 . 336000
= 168000 J
= 168 kJ
Q-ABC = Q-AB + Q-BC
= 10,5 kJ + 168 kJ
= 178,5 kJ (D)
*Keterangan
m = massa
Δt = suhu akhir - suhu awal
C es = massa jenis es
L = kalor lebur
C = 2100 J/kg°c
L = 336.000 J/kg
Δt = 10
jawab : = m x L
= 0,5 kg x 336000 J/kg
= 168000 J
= m x c x Δt
= 0,5 x 2100 x 0
= 0 J
= 168000 + 0
= 168000 J = 168 KJ