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m = 8kg
Q = 3,02x10⁶ J = 3020000 J
c = 4200 /⁰C
T₁ = 27⁰C
ditan
T₂
penyelesaian
Q = m . c . ΔT
ΔT =
T₂ - T₁ =
T₂ - 27 =
T₂ - 27 = 89,8
T₂ = 116,8
jadi suhu akhir adalah 116,8⁰C
2.................
diket
L₀ = 8 m
ΔT = 180-25 = 155⁰C
α = 1,7x10⁻⁵ = 0,000017⁰C
ditan
L
penyelesaia
L = L₀ (1 + α.ΔT)
L = 8 (1 + 0,000017 . 155)
L = 8 (1 + 0,002635)
L = 8 + 0,002108
L = 8,002108
jadi panjang akhirnya adalah 8,0002108 m
jangan lupa dipelajari
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