Sutr1sn0
SEGITIGA ABC siku-siku di B Cos a = 4/5 Tan b = 1 BC = BD = 3 AD = 1 (a) AC = 5 jika AD = a jadi AB = a + 3 a] AC^2 = AB^2 + BC^2 AC^2 = (a + 3)^2 + 3^2 AC^2 = a^2 + 6a + 9 + 9 AC^2 = a^2 + 6a + 18 AC = akar [a^2 + 6a + 18] b] DC^2 = DB^2 + BC^2 DC^2 = 3^2 + 3^2 DC^2 = 9 + 9 DC^2 = 18 DC = akar 18 DC = akar 9 × 2 DC = 3 akar 2
Verified answer
Cos alfa=4/5berarti sampingnya 4
miringnya 5
jadi panjang AB=4
panjang AC =5
tan beta=1
depan/samping
3/x=1
x=3
jadi panjang DB=3
DC²=3²+3²
DC=3√2
terimakasih
Cos a = 4/5
Tan b = 1
BC = BD = 3
AD = 1 (a)
AC = 5
jika AD = a jadi AB = a + 3
a] AC^2 = AB^2 + BC^2
AC^2 = (a + 3)^2 + 3^2
AC^2 = a^2 + 6a + 9 + 9
AC^2 = a^2 + 6a + 18
AC = akar [a^2 + 6a + 18]
b] DC^2 = DB^2 + BC^2
DC^2 = 3^2 + 3^2
DC^2 = 9 + 9
DC^2 = 18
DC = akar 18
DC = akar 9 × 2
DC = 3 akar 2