Question

Ada yang bisa bantu??

Answer 1

Jika :
â=30° vt=0. n=nk
V0=v. g=g

maka nilai v:
jawab:

sinâ=h/s30°=h/s

0.5=h/s

s=2h


w=deltaEk

fs=Ek(akhir)-Ek(awal)


(-w.sinâ-fs) =0-Ek(awal)

-(w.sinâ+fs)s=-Ek(awal)

(m.g.sinâ+nk.N)s=-Ek(awal)

(m.g.sinâ+nk.m.g.cosâ)s=Ek(rot)+Ek(trans)

(m.g.sinâ+nk.m.g.cosâ)s=½lw²+½mv²

(m.g.sinâ+nk.m.g.cosâ)s=½(mR)²(v/

R)²+½mv²

(m.g.sinâ+nk.m.g.cosâ)s=½mv²+½mv²

m(g.sinâ+nk.m.g.cosâ)s=mv²


v²=(g.sin30°+nk.g.cos30°)(2h)

v²=(½g+√3/2g.nk)(2h)

v=√(h.g)(1+√3nk).

maaf klo ada yg salah.