" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x^2 + y^2 = 178 ...............(2)
subtitusi (1) ke (2) diperoleh :
x^2 + (16 - x)^2 = 178
x^2 + 256 - 32x + x^2 = 178
2x^2 - 32x + 78 = 0 ( dibagi 2)
x^2 - 16x + 39 = 0
(x - 13)(x - 3) = 0
x = 13 atau x = 3
untuk x = 13, subtitusi ke (1) diperoleh :
y = 16 - 13 = 3
untuk x = 3, subtitusi ke (1) diperoleh :
y = 16 - 3 = 13
maka selisih kedua bilangan tersebut adalah 13 - 3 = 10
a+b = 16
a²+b² = 178
a² +b² = (a+b)² - 2ab
2ab = (a+b)² - (a²+b²) = 16² - 178 = 78
.
(a-b)^2 = a²+b² - 2(ab)= 178- 78 = 100
a-b = 10.
.
13) Jawab E
2x² - 3x + 10 = x² -6x + 8
x² + 3x +2 = 0
(x+2)(x+1)= 0
x = -2 --> y = x^2 - 6x + 8 = 24
x = -1 --> y = 15
.
14).jawab E
2x² + x +3 = x²- 3x
x² + 4x +3 = 0
(x + 3)(x + 1) = 0
x = -3 --> y = x² -3x = 18
x = -1 --> y = 4
15)
x- 2y = 3 --> x = 2y + 3 substitusi ke xy +y² = 0
(2y+3)(y) + y² - 0
2y² + 3y +y² = 0
3y² + 3y = 0
3y (y + 1) = 0
3y = 0 --> y = 0 --> x = 2y+3 = 3
y+1 = 0 --> y = -1 --> x = 1
salah satu x = 1