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CaC2 + 2 H2O = Ca(OH)2 + C2H2
64g ------------------------ 1 mol
x ------------------------ 5 moli
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x = 320 g czystego CaC2
320 g-------------- 80%
y -------------- 100%
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y = 320gx100%/80% = 400 g 80% CaC2/zanieczyszcz./
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