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L = 1/2 AC BC sinC
so,
1/2 a t = 1/2 AC BC sinC
sinC = a t/(AC BC)
sinC = 6 * 4/(5 * 5) = 24/25
(notice : t = 4 diperoleh dg mggunakan triple pythagoras)
Cos C = AC² + BC² - AB²
2ACAB
= 5² + 5² - 6²
2(5)(6)
= 50 - 36
60
= 14/60
= 7/30
Sin C = √851
30