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A x A = {(2,2); (2,3); (2,4); (2,5); (2,8); (2;10); ... ; (10,5); (10,8); (10,19)}
Debes ver cuáles pares suman 12:
2 + 10 = 12
4 + 8 = 12
10 + 2 = 12
8 + 4 = 12
Entonces el rango es:
R = {(2,10); (4,8); (10,2); (8,4)}
La intersección del rango y el dominio en este caso sería el rango:
A² ∩ R = {(2,10); (4,8); (10,2); (8,4)}
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