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ar² + ar³ = 243
Karena
ar² + ar³ = a.r² + a.r.r² = r² (a+ar)
maka
ar² + ar³ = 243
r² (a+ar) = 243 ----> subtitusikan a+ar = 3
r² . 3 = 243
r² = 243 / 3
r² = 81
r = √81
r = 9
Jadi nilai r adalah 9.
a(1 + r) = 3
( 1 + r ) = 3/a
ar² + ar³ = 243
ar²(1 + r) = 243
(1 + r) = 243/ar²
3/a = 243/ar²
243a = 3ar²
a(243) = a(3r²)
243 = 3r²
243/3 = r²
81 = r²
r = √81
r = 9