Question

a)(4x+1)^2-(2x+1)^2=(3x+1)^2 b) 3(x+2)^2-2(x-2)(x+3)=8 c)(5x+1)^2+x=(2x+5)^2-12 Błagam o pomoc

Answer 1

a) 16x^2+8x+1-4x^2-4x-1-9x^2-6x-1=0

3x^2-2x-1=0

delta: 4-4*3*(-1)=16

x1= 1 x2=-1/3

b) 3x^2+12x+12-2x^2-2x+12-8=0

x^2+10x+16=0

delta: 100-4*1*16=36

x1=-8 x2=-2

c) 25x^2+10x+1+x=4x^2+20x+13

21x^2-9x-12=0

delta: 81-4*21*(-12)=1089

x1=1 x2=0,57