Question

A.(2p+8) (2p-8)
B.(3x+6)²
C.(4y-5)²
Tolong beserta caranya

Answer 1

A. (2p + 8) (2p - 8) = 2p x 2p + 2p x (-8) + 8 x 2p + 8 x (-8) = 4p² -16p + 16p - 64 = 4p² - 64.

B. (3x + 6)² = (3x + 6) (3x + 6) = 3x x 3x + 3x x 6 + 6 x 3x + 6 x 6 = 9x² + 18x + 18x + 36 = 9x² + 36x + 36.

C. (4y - 5)² = (4y - 5) (4y - 5) = 4y x 4y + 4y x (-5) + (-5) x 4y + (-5) x (-5) = 16y² - 20y -20y + 25 = 16y² - 40y + 25.

Answer 2

A.(2p+8) (2p-8)
= 2p (2p-8) + 8 (2p-8)
= 4p² - 16p + 16p - 64
= 4p² - 64

B.(3x+6)²
= (3x+6) (3x+6)
= 3x(3x+6) + 6(3x+6)
= 9x²+18x+18x+36
= 9x²+36x+36

C.(4y-5)²
= (4y-5) (4y-5)
= 4y(4y-5) -5(4y-5)
= 4y²-20y-20y+25
= 4y²-40y+25