November 2018 2 34 Report

a) rozwiąż równania :D
a) 4(x-3) = 20
b) 6(2x+1) = 3(3x-8)
c) -2( 3x – 1 ) -3 = -4
d) 3k – (10+k) = 8
e) 4+ 2(x-1)= 6
f) 5-2(y+3) = 8
g) -1 + 4(2z -1 ) = 3
h) 2y + 3(4 –y ) = y
i) 6(3y+2) – 5(4y+6)= -6
j) -7(2z-3)- 5(4-3z) = 1
k) 0 = -8(x+3) + 4(2x-6)
l) 3= -3(5y+2) -6(3y-7)
ł) 2(7x-3)= 5- 4(6-4x)
m) 2(9y-1) – 3(2y+1) +1 = 5(4y+3)
n) -3-5(3x-2) = -8
o) 4z – 3(3z-5) = 2z+1
p) 8(2x-1) + 3(4-5x)=0
r) -4 (x-2) = 8 – 2(2x-5)
s) x-4 +3( 3 – 2x) = 6(x-1)
t) 3y -2 [5(y-1) -4] = 4(7-3y)

Błagam o szybką odpowiedź i żeby wszystkie były zrobionę . DAM NAJ ! :D


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