A, B, dan C mempunyai beberapa manik-manik. Perbandingan manik-manik mereka adalah A:(A+B+C) =1:4. B:(A+C) = 1:2. C mempunyai 30 manik-manik lebih banyak dari B. Berapa manik-manik yang dimiliki B? Mohon dijawab. Terima Kasih
stefanigifta
T = total A = 1/4t B = 1/3t C = 1t - 1/4t - 1/3t = 12/12t - 3/12t - 4/12t = 5/12t
C - B = 30 5/12t - 1/3t = 30 5/12t - 4/12t = 30 1/12t = 30 t = 30 x 12 = 360
B = 1/3t = 12/36t = 120/360 x 360 = 120
Jadi, manik manik B jumlahnya 120.
Silakan dicek, betul kok^^ Semoga dapat membantu ya^^
A = 1/4t
B = 1/3t
C = 1t - 1/4t - 1/3t = 12/12t - 3/12t - 4/12t = 5/12t
C - B = 30
5/12t - 1/3t = 30
5/12t - 4/12t = 30
1/12t = 30
t = 30 x 12 = 360
B = 1/3t = 12/36t = 120/360 x 360 = 120
Jadi, manik manik B jumlahnya 120.
Silakan dicek, betul kok^^
Semoga dapat membantu ya^^
B = 120
C = 150
Semoga Membantu yaa
Sama-sama