Question

A) (3√7-√2)^2 b)(2trzeciego stopnia√3+3trzeciego stopnia√2)^3 ^ - do potęgi

Answer 1

a)   

(3√7-√2)² = (3√7)²-2·3√7·√2 + (√2)² = 63-6√14+2 = 65-6√14

b)   

(2∛3 + 3∛2)³ = (2∛3)³+3(2∛3)²·3∛2+3(2∛3)(3∛2)²+(3∛3)³ =  

= 8·3+3·4∛9·3∛2+6∛3·9∛4+27·2 =

= 24+36∛18+54∛12+54 =

= 78+36∛18+54∛12

 

 

 

(a-b)² = a²-2ab+b²

(a+b)² = a²+2ab+b²

(a+b)³ = a³+3a²b+3ab²+b³

(a-b)³ = a³-3a²b+3ab²-b³