a) 2 x (-3) -3 x (-2) =
b)(-2) x 6 -4 + 5 =
c) -3+4x(-2)+6=
d)2x(-3)-3x(-2)=
f)4+(-12):(-2)x(-6)=
g)(-2)x6-4+5=
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a. -6+6=0
b. -12-4+5=-11
c. -3-8+6= -7
d. -6+6 = 0
f. 4-12:(-2)*(-6) = 4-36 = -32
g. -12-4+5 = -11
rozumiem że to ''x'' miało oznaczać mnożenie, a nie niewiadomą/
a) 2 x (-3) -3 x (-2) = (-6) - (-6) = - 6 + 6 = 0
b)(-2) x 6 -4 + 5 = - 12 - 4 + 5 = - 16 + 5 = -11
c) -3+4x(-2)+6= - 3 + (-8) + 6 = - 11 + 6 = - 5
d)2x(-3)-3x(-2)= - 6 - (-6) = - 6 + 6 = 0
f)4+(-12):(-2)x(-6)= 4 + 6 x (-6) = 4 + (-36) = -32
g)(-2)x6-4+5= - 12 - 4 + 5 = - 16 + 5 = -11