Question

(9^x . b^2 . 7^y)^4 = 9^20 . b^z . 7^8 , maka nilai x + y + z = ......

Answer 1

(9^x . b^2 . 7^y)^4 = 9^20 . b^z . 7^8
9^(4x) . b^8 . 7^(4y) = 9^20 . b^z . 7^8

9^(4x) = 9^20
4x = 20
x = 20 : 4
x = 5

b^8 = b^z
z = 8

7^(4y) = 7^8
4y = 8
y = 8 : 4
y = 2

x + y + z = 5 + 2 + 8 = 15