Question

Lim 3x / √9+x - √9-x = ...............
x->0


Mahon dgn Penjelasannya

Answer 1

Turunkan fungsi limit :

3x = 3

√9+x = 1 / 2√9+x

√9-x = -1 / 2√9+x

sehingga fungsi akan menjadi :

3 / (1/2√9+x) - (-1/2√9+x)
= 3 / (1/2√9) + (1/2√9)
= 3 / (1/6) + (1/6)
= 3 / (2/6)
= 3 / (1/3)
= 9