Wiedząc, że log 3=0,5 i log 7=0,8 oblicz:
a. log 1/9
b. log243
a. log 1/9 = log 3^(-2) = 2 * log 3 = -2 * 0,5 = - 1
b. log243 = log 3^5 = 5 * log 3 = 5 * 0,5 = 2,5
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a. log 1/9 = log 3^(-2) = 2 * log 3 = -2 * 0,5 = - 1
b. log243 = log 3^5 = 5 * log 3 = 5 * 0,5 = 2,5