BARDZO WAŻNE. Proszę o obliczenie tego przykładu. Powinno wyjść według odpowiedzi 11 [matematyka z plusem 2 z.4 c ; s. 35) (1i1/3)^3 * (-3i3/4)^2 / 3 - 1/9 =
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(1i1/3)^3 * (-3i3/4)^2 / 3 - 1/9 =
=(4/3)³*[(-15/4)²/3]-1/9=
=64/27*[(225/16)/3]-1/9=
=64/27*(225/16*1/3)-1/9=
=64/27*75/16-1/9=
=(4*25)/9-1/9=
=100/9-1/9=
=99/9=
=11
licze na naj
(1i1/3)^3 * (-3i3/4)^2 / 3 - 1/9 =
=(4/3)^3*(-15/4)62/3-1/9=64/27*[(225/16)/3]-1/9=64/27*(225/16*1/3)-1/9=64/27*75/16-1/9=100/9-1/9=11