3^(x+1)+3^x≤(4/9) policzy ktoś? mile widziane też uzasadnienie ;)
rozwiazanie w zalaczniku
3^(x+1)+3^x≤(4/9)
3^x * 3^1 + 3^x ≤ 4/9
3 * 3^x + 3^x ≤ 4/9
4 * 3^x ≤ 4/9 /:4
3^x ≤ 4/9 * 1/4
3^x ≤ 1/9
3^x ≤ 3^(-2)
x ≤ -2
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rozwiazanie w zalaczniku
3^(x+1)+3^x≤(4/9)
3^x * 3^1 + 3^x ≤ 4/9
3 * 3^x + 3^x ≤ 4/9
4 * 3^x ≤ 4/9 /:4
3^x ≤ 4/9 * 1/4
3^x ≤ 1/9
3^x ≤ 3^(-2)
x ≤ -2